Evidence for a highly deformed band inO16+16O breakup ofS32

A study of the ${}_{}{}^{12}{}_{}{}^{}\mathrm{C}$ ${(}^{24}$Mg${,}^{16}$O ${}_{}{}^{16}{}_{}{}^{}\mathrm{O}$ ${)}^4$He reaction has revealed ${}_{}{}^{16}{}_{}{}^{}\mathrm{O}$ + ${}_{}{}^{16}{}_{}{}^{}\mathrm{O}$ breakup from states in ${}_{}{}^{32}{}_{}{}^{}\mathrm{S}$ in the excitation region ranging from 32 to 38 MeV. The spins of the states near 33, 35, and 38 MeV of excitation, obtained from angular correlations, are measured to be (${10}^{+}$ or ${12}^{+}$), (${12}^{+}$ or ${14}^{+}$), and (${14}^{+}$ or ${16}^{+}$), respectively. These may be interpreted as arising from a highly deformed band in ${}_{}{}^{32}{}_{}{}^{}\mathrm{S}$. © 1996 The American Physical Society.