Enthalpies of formation of [M(η-C5H5)2(OOCR)2] complexes; M = Mo, W, or Ti and R = C6H5or CF3
- 1 January 1981
- journal article
- research article
- Published by Royal Society of Chemistry (RSC) in J. Chem. Soc., Dalton Trans.
- No. 5,p. 1174-1177
- https://doi.org/10.1039/dt9810001174
Abstract
The standard enthalpies of formation of the title crystalline solids at 298.15 K have been determined by reaction–solution calorimetry. The results gave ΔHf ⊖{[Mo(η-C5H5)2(OOCC6H5)2], c}=–486.2 ± 3.4, ΔHf ⊖{[Mo(η-C5H5)2(OOCCF3)2], c}=–1 952.0 ± 3.9, ΔHf ⊖{[W(η-C5H5)2(OOCC6H5)2], c}=–448.9 ± 3.5, ΔHf ⊖{[W(η-C5H5)2(OOCCF3)2], c}=–1 914.5 ± 3.8, ΔHf ⊖{[Ti(η-C5H5)2(OOCC6H5)2], c}=–775.2 ± 8.1, and ΔHf ⊖{[Ti(η-C5H5)2(OOCCF3)2], c}=–2 219.0 ± 8.0 kJ mol–1. The metal–oxygen mean bond-enthalpy contributions have been derived as (Mo–OOCC6H5)≈ 305, (W–OOCC6H5)≈ 342, (Ti–OOCC6H5)≈ 432, (Mo–OOCCF3)≈ 300, (W–OOCCF3)≈ 337, and (Ti–OOCCF3)≈ 417 kJ mol–1.Keywords
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