Abstract
The splitting of the energy levels of the lowest triplet state of the benzene molecule has been calculated. The splittings were calculated with the aid of first‐order perturbation theory from antisymmetrized wave functions, which were composed of linear combinations of Slater orbitals. In the absence of an exterior magnetic field the triplet levels are split as a consequence of the spin‐spin interaction, the effect of spin‐orbit interaction may be neglected. The result is a doublet and a singlet; the separation of the two levels is 0.15 cm—1 for the 3B1u state and 0.09 cm—1 for the 3B2u state.

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