Abstract
A relation between the energy-weighted sum rules for nuclear photoabsorption and nuclear muon capture is derived and is used to show that, at least in the case of nuclei with Z=AZ, the mean energy of the neutrinos emitted in muon capture does not vary appreciably as A and Z vary. The Foldy-Walecka expression for the total muon-capture rate is rederived on the basis of the energy-weighted sum rule and is used to show that, at least in the case of nuclei with Z=AZ, and apart from the difference in ground-state energy between the nuclei [Z1, A=2Z] and [Z, A=2Z], the mean energy of excitation of [Z1, A=2Z] due to muon capture is essentially equal to the energy of the giant dipole resonance in [Z, A=2Z].

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