Reactions of low-valent metal complexes with fluorocarbons. Part XV. Acetylacetonatobis(methyldiphenyl- or triphenyl-phosphine)rhodium
- 1 January 1970
- journal article
- research article
- Published by Royal Society of Chemistry (RSC) in J. Chem. Soc. A
- p. 3166-3171
- https://doi.org/10.1039/j19700003166
Abstract
Heptafluoroiodo-n-propane and pentafluorobenzoyl chloride oxidatively add to acetylacetonatobis(methyldiphenylphosphine)rhodium to form the rhodium(III) complexes [Rh(acac)(Ph2PMe)2(C3F7)I] and [Rh(acac)(Ph2PMe)2(COC6F5)Cl]. Treatment of [Rh(L)2(acac)] with pentafluorobenzene sulphonyl chloride affords the five-co-ordinate complexes [Rh(acac)(L)(SO2C6F5)Cl](L = Ph2PMe or Ph3P). Tetrafluoroethylene and chlorotrifluoroethylene react with [Rh(Ph2PMe)2(acac)] to give respectively the rhodacyclopentane complexes [Rh(CF2)4(acac)(Ph2PMe)2] and [Rh(acac)(Ph2PMe)2(C2F3Cl)2]. Bromotrifluoroethylene yields instead [Rh(acac)(Ph2PMe)2(C2F3Br)]. In contrast, [Rh(Ph2PMe)2(acac)] reacts with 1,2-dichlorotetrafluorocyclobutene to form a vinyl complex [Rh(acac)(Ph2PMe)2(C4F4Cl)Cl]. Hexafluoroacetone reacts with [Rh(Ph2PMe)2(acac)] to form [Rh(acac)(Ph2PMe)2{(CF3)2CO}] whereas [Rh(Ph3P)2(acac)] gives a five-membered ring compound (acac)(Ph3P)[graphic omitted]. Treatment of both [Rh(Ph2PMe)2(acac)] and [Rh(Ph3P)2(acac)] with hexafluoroisopropylideneamine leads to displacement of phosphine and the formation of [Rh(acac)(L){(CF3)2CNH}](L = Ph2PMe or Ph3P). The complex [Rh(acac)(Ph2PMe)2{(CF3)2CO}] reacts with tetrafluoroethylene to give (acac)(Ph2PMe)2[graphic omitted].Keywords
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