A spectroscopic study of the F(0+u) ion-pair state of Br2 by the double resonance method

Abstract
A new ion‐pair state of Br2 has been observed by an optical–optical double resonance technique utilizing ultraviolet fluorescence detection. The OODR excitations proceed in an one‐photon resonant three‐photon absorption through the B3Π (0+u) state. The effects of polarization on their transition strengths are used to determine the symmetry of excited molecular state formed by two‐photon absorption from the B state. The results indicate that the new state has the 0+u symmetry with Te=53 899.6(7) cm1, ωe=155.8(2) cm1, and re=3.276(8) Å for 79Br2. This state is expected to correlate with Br+(3P0)+Br(1S) and named F (0+u) after the well‐defined I2 molecule. The single rovibronic fluorescence spectra of the F(0+u) state show several transitions terminating on low‐lying valence states.

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