The Spin and Quadrupole Moment ofO17

Measurements of the quadrupole splitting caused by the ${\mathrm{O}}^{17}$ nuclear spin in the $J=1\mathrm{}\to 2$ transition of the ${\mathrm{O}}^{17}$ ${\mathrm{C}}^{12}$ ${\mathrm{S}}^{32}$ pure rotational spectrum show that the spin of ${\mathrm{O}}^{17}$ is 5/2 and its quadrupole coupling constant is -1.32±0.07 mc. From this coupling constant, the quadrupole moment of the ${\mathrm{O}}^{17}$ nucleus can be estimated as $Q=-5\mathrm{}\times {10}^{-27\mathrm{}}$ ${\mathrm{cm}}^2$. ${\mathrm{O}}^{17}$ appears to fit the extreme single particle model of the nucleus exceptionally well.