Gamma Rays from ${\mathrm{N}}^{15}(p, \alpha \gamma ){\mathrm{C}}^{12}$ and ${\mathrm{N}}^{15}(p, \gamma ){\mathrm{O}}^{16}$

A new resonance in the reaction ${\mathrm{N}}^{15}(p, \alpha \gamma ){\mathrm{C}}^{12}$ giving the 4.43-Mev $\gamma$ ray from the first excited state of ${\mathrm{C}}^{12}$ has been found at a proton energy of 1.64±0.03 Mev. The angular distribution of the $\gamma$ rays indicates that the resonant state in the compound nucleus ${\mathrm{O}}^{16}$ at an excitation energy of 13.65 Mev has spin and parity equal to $1^{+}$ or $2^{-}$. The resonance at 1.05-Mev proton energy has been reinvestigated. At this resonance the capture $\gamma$ rays from the reaction ${\mathrm{N}}^{15}(p, \gamma ){\mathrm{O}}^{16}$ are found to be isotropic, which indicates that this 13.09-Mev level of ${\mathrm{O}}^{16}$ has spin equal to 1. A search was made for capture $\gamma$ rays at the 0.340-Mev resonance of ${\mathrm{N}}^{15}(p, \alpha ){\mathrm{C}}^{12}$ but there were less than 1 percent of the number at the 1.05-Mev resonance. Therefore, it seems that these two levels do not have identical spin, parity, and isotopic spin values.