Band termination in theN=Zodd-odd nucleus46V

High spin states in the odd-odd $N=Z$ nucleus ${}^{46}\mathrm{V}$ have been identified. At low spin, the $T=1\mathrm{}$ isobaric analog states of ${}^{46}\mathrm{Ti}$ are established up to $I^{\pi }{=6\mathrm{}}^{+}.$ Other high spin states, including the band terminating state, are tentatively assigned to the same $T=1\mathrm{}$ band. The $T=0\mathrm{}$ band built on the low-lying $3^{+}$ isomer is observed up to the ${1f}_{7/2}$-shell termination at $I^{\pi }{=15\mathrm{}}^{+}.$ Both signatures of a negative parity $T=0\mathrm{}$ band are observed up to the terminating states at $I^{\pi }{=16\mathrm{}}^{-}$ and $I^{\pi }{=17\mathrm{}}^{-},$ respectively. The structure of this band is interpreted as a particle-hole excitation from the ${1d}_{3/2}$ shell. Spherical shell model calculations are found to be in excellent agreement with the experimental results.