Energy Level at 31 Kev inAl28fromAl27(d,p)Al28Reaction

The proton group previously assigned to the ground state of ${\mathrm{Al}}^{28}$ from the ${\mathrm{Al}}^{27}\mathrm{}(d,p)\mathrm{}{\mathrm{Al}}^{28}$ reaction has been found to be a doublet, the low energy member of which is ascribed to an excited state at 31.2±2.0 kev. The $Q$-value corresponding to the ${\mathrm{Al}}^{28}$ ground state has been measured as 5.494±0.010 Mev. The $Q$-value corresponding to the ground state of ${\mathrm{Mg}}^{25}$ in the ${\mathrm{Al}}^{27}(d,\alpha ){\mathrm{Mg}}^{25}$ reaction is 6.694±0.010 Mev, and the first excited level in ${\mathrm{Mg}}^{25}$ is at 0.584±0.006 Mev.